CF(A) = 0.6*0.9 = 0.54
 CF(A&B) = min(0.54, 0.8) = 0.54
 CF(Hv(A&B)) = max(0.8, 0.54) = 0.8
 CF(C) = 0.9*0.8 = 0.72
 CF(D) = 0.8*0.7 = 0.56
 CF(CvD) = max(0.72, 0.56) = 0.72
 CF(E) = 0.75*0.72 = 0.54

                    I     II      III
1  has no car      OUT    IN      OUT
2  < 18 years      OUT    IN      IN
3  millionaire     OUT    OUT     IN
4  win on horses   OUT    OUT     OUT
5  univ. teacher   OUT    OUT     IN

      1 is in if 2 is in and 3 is out
      3 is in if 4 or 5 is in

      eval[ (foo (quote (a b)) (quote (b c))) ]
			eval[ (quote (a b)) ]
			(a b)
					eval[ (quote (b c)) ]
					(b c)
	apply[ foo, ((a b) (b c)) ]
	apply[ (lambda (x y) (cons (car x) y)),((a b) (b c)) ]
	eval[ (cons (car x) y)), ((x (a b))(y (b c))) ]
			eval[ (car x), ((x (a b))(y (b c))) ]
				eval[ x, ((x (a b))(y (b c))) ]
				(a b)
			apply[ car, ((a b)) ]
			a
					eval[ y, ((x (a b))(y (b c))) ]
					(b c)
	apply[ cons, (a (b c)) ]
	(a b c)